Joshua0317 said:

Well an inverse that is a function doesn't exist but by inverse I meant reverse mapping. I don't work well with words, but if you give me the function I will look at it and see what I come up with.

Gorgon the Wonder C0w said:

It looks like an integral for a range, or perhaps coordinates. What I've never seen before is a bracket on the open end and a parenthesis on the close end. That is confusing me. But the last time I did calculus was a half decade ago.

I have a friend with a PhD in the maths. I have e-mailed him to see what he has to say.

wolf said:

Let me go into math teacher mode now:

f([0, ln2)) is a set, and is called the image of the interval [0,ln2) under the function f. It is the set {f(x) such that x is in [0, ln2)}. To generate this set, you go through every point in the interval [0, ln2), apply the function f, and collect the results in the set f([0, ln2)).

For f(x)=e^x, it is simple to determine f([0,ln2)) because e^x is continuous and strictly increasing. Strictly increasing means that if 0<x<ln2, then e^0<e^x<e^(ln2). Since e^x is continuous, the Intermediate Value Theorem says that if e^0<y<e^(ln2), then there is x in (0, ln2) such that y=e^x. These observations allow you to determine e^([0,ln2)) very easily.

Gorgon the Wonder C0w said:

xD. Sorry I couldn't get it to you faster.

awesomeguy said:

He might have meant 14 * -3