First, you must break up the south-of-east force into its components. You can do this using trig.
From here you add the x-componet of the south-of-east force to the eastern force to get a force in the x direction of 1.1204. Because F=ma, the acceleration in a given direction is F/m. So, the acceleration in the x and y directions are as follows:
You then plug this into your postion functions (a/2)t^2 + vt + x to determine position:
x-position: .4482(3)^2 + .11(3) = 4.3638
y-position: .06389(3)^2 = .575
From here, you use the pythagorean theorem to determine magnitude of displacement:
Sqrt[4.3638^2 + .575^2] = 4.4015 meters
You can then use any number of various trig operations to find the angle:
theta = 7.506 degrees south of east
I'm sorry I couldn't give you any vector diagrams. Hopefully you can figure it out. (Double check the math as well).