a2 = b2 + c2 - 2bc * cos(θ)
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 If you have math problems, post here. [Quote] [Link]
 Not really a problem but just a question. Explain how Sine-1 turns sine into an angle, usually theta :P [Quote] [Link]
 Sophrosyne Administrator3144 Posts11 Ineo 3:1 - 12.85.44772.816 days ago Arcsine undoes Sine. The information you gather from a triangle is the Sine of ABC, which is not useful in finding the angle measurement. We can undo Sine though with Arcsine, just like how the sqrt(x2) == x. At least, I think that's how it is explained. [Quote] [Link]
 This might be a bit vague, but here goes. Given: (x+3)^2 Find: f(x+h) Any help? [Quote] [Link]
 Sophrosyne said:Arcsine undoes Sine. The information you gather from a triangle is the Sine of ABC, which is not useful in finding the angle measurement. We can undo Sine though with Arcsine, just like how the sqrt(x2) == x. At least, I think that's how it is explained. ... but how does putting sine under a sign that means "basically" to give the reciprocal... how does that worK? [Quote] [Link]
 Hydrogen777 Administrator5467 Posts11 Ineo 3:1 - 15.46.78772.685 days ago Burrito Famine said:This might be a bit vague, but here goes. Given: (x+3)^2 Find: f(x+h) Any help?Are you not given the original function f? I'm a little lost as to what is being asked. [Quote] [Link]
 I'm only asking why you get the angle that creates the ratio of Sine when you press Sin-1 Yes, I understand what ArcSine is, but how does getting a reciprocal reproduce the angle? [Quote] [Link]
 Hydrogen777 Administrator5467 Posts11 Ineo 3:1 - 15.60.53772.679 days ago Ah, it's not a reciprocal. The symbol is a bit misleading. The -1 simply means that it's the inverse function, not that it's the multiplicative inverse (reciprocal). Edit: In other words, sin-1 is just a function designed to return the angle that yields whatever sine value is given it. [Quote] [Link]
 The -1 doesn't actually mean the reciprocal - it's notational shorthand for arcsin. In the same way that x-1(x(a)) = a, sin-1(sin(a)) = a. Also, to the function question: If you mean that f(x) = (x + 3)2, then f(x+h) = ((x+h)+3)2. Everywhere you see x in the original function, replace it with (x+h). [Quote] [Link]
 Hydrogen777 said:Ah, it's not a reciprocal. The symbol is a bit misleading. The -1 simply means that it's the inverse function, not that it's the multiplicative inverse (reciprocal). so what's an inverse function? [Quote] [Link]
 Hydrogen777 Administrator5467 Posts11 Ineo 3:1 - 15.65.88772.676 days ago It is a function that "undoes" a corresponding function. The inverse of the function "f(x) = x + 1" for example would be "f-1(x) = x - 1". [Quote] [Link]
 Hydrogen777 said:Burrito Famine said:This might be a bit vague, but here goes. Given: (x+3)^2 Find: f(x+h) Any help?Are you not given the original function f? I'm a little lost as to what is being asked. So am I. But its on my homework and I haven't the slightest clue on what to do. I don't even know what it is asking. Oh well... [Quote] [Link]
 Burrito Famine said:This might be a bit vague, but here goes. Given: (x+3)^2 Find: f(x+h) Any help? I dunno. If f(x)=(x+3)2, then f(x+h) would be: f(x+h)=[(x+h)+3]2 f(x+h)=(x+h+3)2 f(x+h)=x2+h2+9+2hx+6x+6h f(x+h)=x2+(2h+6)x+h2+6h+9 [Quote] [Link]
 Thank you Beary! You are a cool cat. [Quote] [Link]
 If this is just a derivative, when f(x)=(x+3)^2, f'(x) = 2(x+3). Easy :) [Quote] [Link]
 Hoooly shit, I'm so fucked if there is no one here to help me, like now! [Quote] [Link]
 Verum Administrator2751 Posts11 Ineo 3:2 - 10.79.77771.919 days ago What are you talking about? [Quote] [Link]
 I have homework due tomorrow, 3 questions only, but I don't know shit about them! And here it's 10:35 pm! [Quote] [Link]
 marymansour said:If this is just a derivative, when f(x)=(x+3)^2, f'(x) = 2(x+3). Easy :) Err, wouldn't it be (x+3)*(x+3), which would make the answer x^2+6x+9? The complications arise when h is introduced. But no matter. I've already turned it in. [Quote] [Link]
 Burrito Famine said:Err, wouldn't it be (x+3)*(x+3), which would make the answer x^2+6x+9? The complications arise when h is introduced. But no matter. I've already turned it in. No, it wouldn't. The Power Rule easily proves when f(x) = (x+3)^2, f'(x) = 2(x+3). As for when h is used, as above, f(x + h) is usually used as part of the formula "lim(h-->0) ( ( f(x+h) - f(x) ) / h )", which, if f(x) = (x+3)^2, will equal 2(x+3). [Quote] [Link]
 Ok, thank you very much. I'm going in for tutorials tomorrow. I obviously don't understand it at all. [Quote] [Link]
 ywkbme said:I have homework due tomorrow, 3 questions only, but I don't know shit about them! And here it's 10:35 pm! Let us help. O_o [Quote] [Link]
 I'm fine, a friend helped me! :D [Quote] [Link]
 My math teacher says that if you've got a geometry problem, and you can't make sense of it, draw random lines that pass through at least one point (preferably 2). You'll eventually get a line that'll make you click. SporeInsanity said:Not really a problem but just a question. Explain how Sine-1 turns sine into an angle, usually theta :P Well, if sin(theta) gives the sine of an angle, then Sin-1(theta) should do the inverse... right? [Quote] [Link]
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The Forum > Math & Science > Math Problem Thread
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