yay! I get the first three powers of 2!

249

and now 10^3/2^2

251

Why didn't anyone correct me? I had 25!

Anyways,
a palindromic number 100x+10y+z , and if you make x and z equal y, and vice versa, then flip it upside down, you get the same number.

The last digit is the product of the first two digits. There are 3 digits in this number The digits are all different. They are all powers of two.

3=2*5

anyways, 254

255

If you don't check your work, I'm not going to do it for you! ;)

2^(2*(2^2))

the 3rd and last digit of this number is the sum of the other two, and all three digits are prime.

The first digit, raised to the power of the second digit minus the first digit, equals the last digit.

the 6th prime number multiplied by 2^2*5

^ One post early.

260 now.

nope, my post is the 263rd.

but it's not the post count, it's the current number that counts.
ergo: 262

263

once again, the first three even numbers. Different order, though.

265

The year that is year 809 in the Thai solar calendar.

Two hundreds three score and seven.

10
110
1000

The first odd prime number multiplied with the first digit is equal to the second digit. The same number added to the second digit is equal to the third digit.

15 * 18

n += 1

..
.......
..