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Please don't peel the stickers off your Rubik's Cube
The Forum > Tomfoolery > Counting to 10,000
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(let (x 27))
(loop 
    (when (= x 10000)(return))
    (print x)
    (incf x))

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if (0 == x) x = 1;
while (x) x++;
printf("%d\n", x);
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third tea cup today!!!
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Octal 41.
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Yes.
I'm going to sit here and assume we're aiming more for 10,000 posts than actually counting to 10,000. Now, that'll take awhile, so we have to do something to ward off the boredom.
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.........
Anyone bring any cards?
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41
NOW THE BIG SURPRISE TO BE FOUND ONCE SOMEONE POSTS THE 100th POST!!!!!
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The act of flipping 4 coins. (4d2)
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Even though this post is yonjuuroku, not yonjuuyon...
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The category page suggests that this should be the ninth abundant number.
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eofpi said:
The category page suggests that this should be the ninth abundant number.


Indeed, and my post above was the weighted average of the eighth and the ninth abundant numbers, with the ninth having twice the weight. Furthermore, I specifically noted that the post was not the weighted average of the above numbers with the eighth having twice the weight, however the following post then asserted that it was such, even though the sequence would have made my previous post be said number, if anything.

Talking about things in an avoidant (which should totally be a word) fashion is rather fun, if not obfuscating.

And this post would be yonjuukyuu.
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The Forum > Tomfoolery > Counting to 10,000
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